Form 3 Mathematics Bab 5: Trigonometric Ratios
In a right-angled triangle relative to an acute angle $\theta$:
Relationship between Sine, Cosine, and Tangent:
$$\tan \theta = \frac{\sin \theta}{\cos \theta}$$The table below summarizes the exact values of trigonometric ratios for $30^\circ$, $45^\circ$, and $60^\circ$:
| Ratio / Angle ($\theta$) | $30^\circ$ | $45^\circ$ | $60^\circ$ |
|---|---|---|---|
| $\sin \theta$ | $\frac{1}{2}$ | $\frac{1}{\sqrt{2}}$ | $\frac{\sqrt{3}}{2}$ |
| $\cos \theta$ | $\frac{\sqrt{3}}{2}$ | $\frac{1}{\sqrt{2}}$ | $\frac{1}{2}$ |
| $\tan \theta$ | $\frac{1}{\sqrt{3}}$ | $1$ | $\sqrt{3}$ |
Since the two acute angles in a right-angled triangle add up to $90^\circ$ (complementary angles):
$$\sin (90^\circ - \theta) = \cos \theta$$ $$\cos (90^\circ - \theta) = \sin \theta$$To find an unknown angle when two side lengths are known, use inverse trigonometric functions:
$$\theta = \sin^{-1}\left(\frac{O}{H}\right)$$ $$\theta = \cos^{-1}\left(\frac{A}{H}\right)$$ $$\theta = \tan^{-1}\left(\frac{O}{A}\right)$$Angles can be measured in degrees ($^\circ$) and minutes ($'$), where $1^\circ = 60'$.